man saves Rs 320 during the first month, Rs 360 in the second month, Rs 400 in the third month. If he continues his savings in this sequence, in how many months will he save Rs 20,000
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Answered by
1
the given sequence is
320,360,400,........20000
a = 320. d = 40
let nth term = 20000
=> 320 + ( n - 1 ) 40 = 20000
=> 32 + 4n - 4 = 2000
=> 4n = 2000-28
=> n. = 1972/4
=> n. = 493
therefore in 493 months he
will have saved Rs 20,000
Answered by
1
Answer:
here is your answer
Step-by-step explanation:
493months he will collect 20,000
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