Man sold 50 kg more than 1/3 of his total quantity of rice .again he sold 50 kg more than 1/2 of the remaining quantity.If the total remaining quantity is 250 kg then how much stock did he originally have?
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Answer:
Answer
Correct option is
B
1800 kg
Let the original stock f rice be x kg Parts of the stock sold first time =(
3
2x
+100)kg
∴ Remaining stock = [x−(
3
2x
+100)]kg=(
3
x
−100)kg
Part of the stock sold second time
=[
2
1
(
3
x
−100)+100]=(
6
x
−50+100)kg=(
6
x
+50)kg
∴ Remaining stock =(
3
x
−100)−(
6
x
+50)=(
3
x
−
6
x
−100−50)kg=(
6
x
−150)kg
Given
6
x
−150=150⇒
6
x
=300⇒x=1800kg
Step-by-step explanation:
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