Man, this is very weird for me how can I work out this AREA ITS A HEGON AND HAS DIFFERENT SIDE NUMBERS :( I just don't understand! please help me :{ :/
Answers
area of rectangle = 5x12 = 60cm^2
area of triangles = 1/2 * base * height
base = 12 cm
height = (13-5)/2
= 8/2 = 4cm
1/2 * 12*4
= 24cm^2
area of 2 triangles = 2x 24 = 48cm^2
area of hexagon = 60+48 = 108cm^2
pls mark as brainliest. If you have any doubts comment on this answer.
Answer:
Ezy see I will explain you, and you marke brainliest :P
Area of this hexagon = Area of rectangle + area of triangle x 2
Area of rectangle= Length x breadth
= 12 x 5 cm
60 (cm^2 )
Area of triangle = 1/2 ( Height x base)
*here height of the total figure is 13cm and 5cm of it is the breadth of the rectangle in it.
13-5 = 8 cm
* there are 2 triangles so , one triangle's height = 8/2cm= 4cm
1/2 (height x base)
= 1/2 ( 4cm x 12cm) base of the traingle is the length of the rectangle.
= 1/2 x 48
= 24 (cm^2)
Area of this hexagon= 60 cm^2 + 24 cm^2 x 2
(60 + 48) cm^2
108 cm^2