Math, asked by karolinasergejeva0, 8 months ago

Man, this is very weird for me how can I work out this AREA ITS A HEGON AND HAS DIFFERENT SIDE NUMBERS :( I just don't understand! please help me :{ :/

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Answers

Answered by Anonymous
1

area of rectangle = 5x12 = 60cm^2

area of triangles = 1/2 * base * height

base = 12 cm

height = (13-5)/2

           = 8/2 = 4cm

1/2 * 12*4

= 24cm^2

area of 2 triangles = 2x 24 = 48cm^2

area of hexagon = 60+48 = 108cm^2

pls mark as brainliest. If you have any doubts comment on this answer.

Answered by Tan1shq3000
2

Answer:

Ezy see I will explain you, and you marke brainliest :P

Area of this hexagon = Area of rectangle + area of triangle x 2

Area of rectangle= Length x breadth

= 12 x 5 cm

60 (cm^2 )

Area of triangle = 1/2 ( Height x base)

*here height of the total figure is 13cm and 5cm of it is the breadth of the rectangle in it.

13-5 = 8 cm

* there are 2 triangles so , one triangle's height = 8/2cm= 4cm

1/2 (height x base)

= 1/2 ( 4cm x 12cm) base of the traingle is the length of the rectangle.

= 1/2 x 48

= 24 (cm^2)

Area of this hexagon= 60 cm^2 + 24 cm^2 x 2

(60 + 48) cm^2

108 cm^2

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