Question

man travels 370 km, partly by train and partly by car.
If he covers 250 km by train and the rest by car, it takes him 4 hours, but if he travels 130km by train and the rest by car he takes 18 min. longer. Find the speed of the train and car.
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Answer 1

Answer:

Step-by-step explanation:

Answer:

Let the speed of the car be C kmph

Let the speed of the train be T kmph

4 hours = 250 km / T kmph + (370 - 250) km / C kmph

        4 = 250/T + 120/C  --> equation 1

4 hrs 18 minutes = 130 km / T kmph + (370 - 130)km / C kmph

      258/60 = 4.3 = 130 / T + 240 / C      --- >         equation 2

Multiply equation 1 by 2 and subtract equation 2 from it.

      8 - 4.3 = 500/T - 130/T + 240/C - 240/C

      3.7 = 370 / T

      T = 370/3.7 = 100 kmph

Substitute the value of T in equation 1 to get,

      4 = 250/T + 120/C  -- > equation 1

      4 = 250/100 + 120/C

      4 - 2.5 = 120/C

      C = 120/1.5 = 80 kmph

The train runs at 100 kmph and the car runs at 80 kmph

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Answer 2

Answer:

let speed of train x km/hour

& Speed of car y km/hour

So time = distance/speed

250/x. + 120/y =4 equation 1

130/x. +. 240/y = 43/10 equation 2

Solve both equation

Step-by-step explanation: