Question

man walked 12 metres to North 4 metres to east and finally climbed a vertical pole national the height of 3m find displacement​

Answer 1

Let the man started from the origin of the 3 dimensional coordinate frame.

Coordinates (Initial)=(0,0,0)

Coordinates (Final)=(4,12,3)

Displacement=

$\sqrt{ {(4 - 0)}^{2} + {(12 - 0)}^{2} + {(3 - 0) }^{2} }$

Displacement=√(16+144+9)

=√169

=13 m