man walks on a straight road from his home to a market 2.5km away with a speed of 5km/h. finding the market closed ,he instantly turns and walks back home with spped of 7.5km/h . the average speed of man over the interval of time 0 to 40 min is equal to:
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Answer:
Did you mean: man walks on a straight road from his home to a market 2.5km away with a speed of 5km/h. finding the market closed ,he instantly turns and walks back home with speed of 7.5km/h . the average speed of man over the interval of time 0 to 40 min is equal to:
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Answer:
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Explanation:
Average speed = total distance /total time
Time taken to go to the market = distance /speed = 2.5 /5 hour= 1 /2 hours=30 minutes
Time taken to return back = distance /speed = 2.5 /7.5 hour=1/3hours=20 minutes
Distance travelled in 10 minutes while returning back= 10/60 ×7.5=1.25km
( Speed is constant at 7.5 km/hr )
Hence Distance traveled in 40 minutes(30 mins towards the market and 10 mins towards home) =2.5+1.25=3.75km
So average speed in 0 to 40 minutes =( 3.75km )/40 /60 hr
= 45/ 8 km/hr