man wishes to estimate the distance of a nearby
tower from him standing at point A in front of tower C he
observed at its peak and then he walk perpendicular to AC up
to B , a distance of 100 m and looks at C again but there is an
angle shift of θ = 40° . Estimate AC.
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Answer:
Explanation:
let he be at point d perpendicular to ac
then sin of 40 is ac/bc
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