मनीषच्या आईचे आजचे वय त्याच्या वयाच्या 5 पटीपेका 1 ने जास्त आहे.4 वर्षापूर्वी त्यांच्या वयाचा गुणाकार 22 असल्यास : त्यांची आजन्ची वये काढा.
Answers
Step-by-step explanation:
Let the present age of Manish be x years.
& the present age of his mother be ( 5x + 1 ) .
4 years ago
Manish' s age = ( 4 - x ) years
His mother's age = [ 4 - ( 5x + 1 ) ]
= ( 4 - 5x -1 )
= 3 - 5x
According to the condition
( 4 - x ) × ( 3 - 5x ) = 22
4 ( 3 - 5x ) - x ( 3 - 5x ) = 22
12 - 20x - 3x + 5x² = 22
5x² - 23x + 12 - 22 = 0
5x² - 23x - 10 = 0
5x² - 25x + 2x - 10 = 0
5x( x - 5 ) +2( x - 5 ) = 0
( x - 5 ) ( 5x + 2 ) = 0
x - 5 = 0 OR 5x + 2 = 0
x = 5 OR 5x = -2 = x = -2/5
But age never be negative ,
x ≠ -2/5
The present age of Manish is 5 years
The present age of his mother = ( 5x + 1 )
= ( 5 × 5 + 1 )
= 25 + 1 = 26
Given : Manish's mother's present age is 1 more than 5 times his age.
4 years ago her age was 22 times
To Find : Present ages
Solution:
Manish age = M year
Manish mother age = 5M + 1 years
4 years ago Manish age = M - 4 year
4 years ag Manish mother age = 5M + 1- 4 = 5M - 3 years
5M - 3 = 22 (M -4 )
=> 5M - 3 = 22M - 88
=> 17M = 85
=> M = 5
Manish age = 5 Years
Manish mother age =26 years
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