Question

Manav has a small box with ₹740 in coins of denomination ₹1, ₹2 and ₹5. If the number of coins of denomination of ₹2 are 3 times the number of coins of denomination of ₹1 and the number of coins of denomination of ₹5 are twice the number of coins of ₹2, how many coins of each denomination does Manav has?

Answer 1

Manav has 20, 60 and 120 numbers of coins of Rs 1, 2 and 5 denomination, respectively

Answer 2

Let the value of one rupee be x

Then two rupee two coin be 3x

Then the value 5 rupee coin =2×3x=6x

Now,

The value of ₹1 coin =x×1 =x

The value ₹ 2 coin =3x×2 =6x

The value of ₹5 coin= 6x×5=30x

A.T.Q

The total denomination = ₹740

x+6x+30x=740

37x = 740

x = 740/37

x = 20

So ,the no. of ₹1 coin = x =20

The no. of ₹2 coin= 3x =3×20 =60

The no. of ₹5 coin = 6x =6×20=120