Math, asked by kusumpoonia599, 8 months ago

Manav has a small box with Rs 740 in coins of denominations Rs 1, Rs 2 and Rs 5. If the number of coins of denominations of Rs 2 are 3 times the number of coins of Rs 1 and the number of coins of denomination of Rs 5 are twice the number of coins of Rs 2. How many coins of each denomination does Manav have? ​

Answers

Answered by keshav4047
19

Step-by-step explanation:

Let us assume x,y,z be no of coins of 1 , 2 and 5 respectively

y = 3x and z = 2y

Value = x+2y+5z = 740 becomes x+2(3x)+5(2)(3x) = 740

37x = 740

x = 20:  y = 60 and z = 120

There are 20 coins of 1 re, 60 coins of Rs. 2 and 120 coins of Rs. 5/-

Answered by abaanasim23
11

Answer:

20 coins of 1 rs, 60 coins of Rs. 2 and 120 coins of 5 rs.

Step-by-step explanation:

Let us assume x,y,z be no of coins of 1 , 2 and 5 respectively

y = 3x and z = 2y

Value = x+2y+5z = 740 becomes x+2(3x)+5(2)(3x) = 740

37x = 740

x = 20:  y = 60 and z = 120

There are 20 coins of 1 re, 60 coins of Rs. 2 and 120 coins of Rs. 5/-

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