Math, asked by stutipantha, 9 months ago

Mandal purchased sugar of different quality at the rate of rs.80 per kg and rs.60 per kg. He mixed both in the ratio of 4:3 and sold it at the rate of rs.72 per kg. Find his gain or loss percent. Please do full explanations.​

Answers

Answered by aarohisingh62
1

Step-by-step explanation:

lets 1 kg of sugar type A, and 5 kg of sugar type B are mixed together in the ratio 1:5 .

Now,

Total quantity of sugar to be sold = 1+5 = 6 Kg.

Cost of type A (1 Kg) sugar = 1 *5 = 5 Rs

Cost of type B (5 Kg)sugar = 5 *6 = 30 Rs

Total cost of 6 Kg sugar to be sold = 5+30 = 35 Rs

Cost Price = 35

Profit = 20%

So, Selling Price = 35 + 35*(20/100) = 35 + (35/5) = 42 Rs.

42 is the S.P of 6 Kgs Sugar.

So, per Kg S.P of sugar = 42/6 = 7 Rs.

A shopkeeper has two types of sugar, one costing RS 60 per kg and another costing RS 80 per kg. If he sells 150 kg of mixed sugar at RS 10400, what is the amount of each type of sugar?

1 kg of sugar is bought at the rate of Rs. 10/kg and the 2nd kg of sugar is bought at Rs. 20/kg. At what price should the 2 kgs of sugar be sold in order to earn 10% profit on the total buying price.?

2 kg of sugar has the cost price of Rs. 4 should be mixed with how many kgs of sugar worth Rs. 5 kg to be sold at 5 Rs/kg gaining 100/9% profit?

If 1kg sugar costs 20 rupees, what will be the price of 1kg of 800gm sugar?

In what ratio must two kinds of sugar at Rs. 1.15 and Rs. 1.24 per kg be mixed so that by selling at Rs. 1.50 per kg, 25% may be gained?

Cost of 1kg variety-1 sugar = Rs. 5

Cost of 5kg variety-2 sugar = 5×6= Rs. 30

Cost of 6kg (1+5) mix variety sugar = Rs. 35

Cost of 1kg mix variety sugar = Rs. (35/6)

Therefore,

Selling price at 20% profit = (35/6)×1.2= Rs. 7/kg.

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Cost of type 1 sugar cost=₹5/kg

Cost of type 2 sugar cost=₹6/kg

Now sugar mixed at a ratio 1:5

Total sugar = (1+5)kg =6 kg

Cost of total sugar CP = ₹(1*5)+(5*6) = ₹5+30

= ₹35

Profit = 20%

Now Profit =₹ (P/100)*CP

₹ (20/100)*35= ₹7

Selling Price SP= CP + Profit

₹35+7 = ₹ 42

Selling price for 1 kg sugar = 42/6= ₹7

I just tried with large numbers.

If Rs.5/Kg and R.s.6/Kg is taken 2Kg and 10Kg respectively. Then

Cost price= (2*5)+(10*6) =70,

Profit=20%.

Selling price = cost price + profit

Sp= 70+ (70*20%)= 84

Rs. 84 for 12 kg of mixture. Then selling price for 1 Kg will be Rs. 7

Answered by sujatatyagi1979
1

Answer:

Step-by-step explanation:Mix, say S kg of sugar at Rs.14 per kg to 15 kg at Rs.20 per kg, or

[14S + 20*15]/(S+15) = 18, or

14S + 300 = 18S + 270, or

4S = 30, or

S = 7.5

So, add 7.5 kg of sugar at Rs.14 per kg to 15 kgs of sugar at Rs.20 per kg to sell the mixture at Rs.18 per kg.

Check: (7.5*14 + 20*15)/(7.5+15) = [105+300]/22.5 = 18. Correct.

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