Question

Mandy throws a stone off a bridge into the river below. The stones height above the water in meters H(t) after t seconds is measured using the function h(t)= -16t^2+32t+43. What is the initial height of the stone?

Answer 1

Given : Mandy throws a stone off a bridge into the river below. The stones height above the water in meters H(t) after t seconds is measured using the function h(t)=  -16t²+32t+43

To find : initial height of the stone

Solution:

The stones height above the water in meters H(t) after t seconds

h(t)=  -16t²+32t+43

initial height of stone

=> t = 0

putting t = 0 in equation

=> h(0) =  -16(0)²+32(0)+43

=> h(0) = 0 + 0 + 43

=> h(0) = 43

Hence the initial height of the stone  = 43 m

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