Question

Manganese forms non stoichiometric oxide having the general formula MnOx. The value of x for a compound that contained 63.7% Mm (Mm is 55)

Answer 1

Answer:- The value of X for the manganese oxide is 2 and the formula of the oxide is $MnO_2$ .

Solution:- We are asked to calculate the value of X which is the subscript of oxygen in the unknown oxide.

From given information, the compound has 63.7% Mn.

percentage of oxygen = 100 - 63.7 = 36.3%

We can calculate the moles for Mn and O as:

$63.7g Mn(\frac{1 mol}{55g})$

= 1.16 mol Mn

and

$36.3g O(\frac{1 mol}{16g})$

= 2.27 mol O

Now we could calculate the mol ratio of these two elements as:

$\frac{2.27 mol O}{1.16molMn}$

= $\frac{2mol O}{1molMn}$

The mol ratio of Mn to O is 1:2. So, the value of X is 2 and the formula of the oxide is $MnO_2$ .