Math, asked by harshita23b, 8 months ago

Manik wanted to draw the graph of the equation 3x + 7y = 42 on a graph paper, with each square on the graph paper having a side of length one unit. How many of the unit squares in the graph paper will have their interiors lying entirely in the first quadrant and entirely below the graph of the given equation?

Answers

Answered by unknownauthor05
0

Answer:

First, rewrite the statement into the slope-intercept form (y = mx + b) which can be easily graphed.

2

Add 7y to each side of the equation. Addition Property of Equality

3

Simplify

4

Subtract 42 from each side of the equation. Subtraction Property of Equality

5

Simplify

6

Divide each side of the equation by 7. Division Property of Equality

7

Simplify

8

Simplify

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Answered by talariri
0

I will not understand this question sorry sorry sorry

Answer:

please

Step-by-step explanation:

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