Manila sold a table and a chair for Rs. 1050, thereby making a profit of 10% on the table and 25% on the chair. If she had taken a profit of 25% on the table and 10% on the chair she would have got Rs. 1065. Find the cost price of each.
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Solution :-
Let the Cost Price of the table and chair be Rs. x and Rs. y respectively.
Situation - 1 (Selling Price of a table and a chair is Rs. 1050 with 10 % profit earned on table and 25 % profit earned on chair.)
Table - 10 % profit earned.
So, Selling Price of the table is -
⇒ SP = x + (x*10)/100
⇒ x + x/10 = 11x/10
So, SP of table is Rs. 11x/10
Chair - 25 % profit earned.
So, Selling Price of the chair is -
⇒ SP = y + (y*25)/100
⇒ y + y/4 = 5y/4
So, SP of chair is Rs. 5y/4
Now, according to the question.
⇒ 11x/10 + 5y/4 = 1050
Taking LCM of denominators and then solving it.
⇒ (22x + 25y)/20 = 1050
⇒ 22x + 25y = 1050*20
⇒ 22x + 25y = 21000 ....................(1)
Situation - 2 (If Manila had taken a profit of 25 % on the table and 10 % on the chair, she would have got Rs. 1065)
Table - 25 % profit earned.
So, Selling Price of the table is -
⇒ SP = x + (x*25)/100
⇒ x + x/4 = 5x/4
So, selling price of the table is Rs. 5x/4
Chair - 10 % profit earned.
So, Selling Price of the chair is -
⇒ SP = y + (y*10)/100
⇒ y + y/10 = 11y/10
Now, according to the question.
⇒ 5x/4 + 11y/10 = 1065
Taking the LCM of denominators and then solving it.
⇒ (25x + 22y)/20 = 1065
⇒ 25x + 22y = 1065*20
⇒ 25x + 22y = 21300 .......................(2)
Now, multiplying equation (1) by 25 and equation (2) by 22, we get
⇒ 550x + 625y = 525000 ............(3)
⇒ 550x + 484y = 468600 ............(4)
Now, subtracting (3) from (4).
550x + 625y = 525000
550x + 484y = 468600
- - -
_____________________
141y = 56400
_____________________
⇒ 141y = 56400
⇒ y = 56400/141
⇒ y = 400
Substituting y = 400 (1)
22x + 25y = 21000
⇒ 22x + (25*400) = 21000
⇒ 22x + 10000 = 21000
⇒ 22x = 21000 - 10000
⇒ 22x = 11000
⇒ x = 11000/22
⇒ x = 500
So, Cost price of table is Rs. 500 and Cost Price of chair is Rs. 400 respectively.
Answer.
Let the Cost Price of the table and chair be Rs. x and Rs. y respectively.
Situation - 1 (Selling Price of a table and a chair is Rs. 1050 with 10 % profit earned on table and 25 % profit earned on chair.)
Table - 10 % profit earned.
So, Selling Price of the table is -
⇒ SP = x + (x*10)/100
⇒ x + x/10 = 11x/10
So, SP of table is Rs. 11x/10
Chair - 25 % profit earned.
So, Selling Price of the chair is -
⇒ SP = y + (y*25)/100
⇒ y + y/4 = 5y/4
So, SP of chair is Rs. 5y/4
Now, according to the question.
⇒ 11x/10 + 5y/4 = 1050
Taking LCM of denominators and then solving it.
⇒ (22x + 25y)/20 = 1050
⇒ 22x + 25y = 1050*20
⇒ 22x + 25y = 21000 ....................(1)
Situation - 2 (If Manila had taken a profit of 25 % on the table and 10 % on the chair, she would have got Rs. 1065)
Table - 25 % profit earned.
So, Selling Price of the table is -
⇒ SP = x + (x*25)/100
⇒ x + x/4 = 5x/4
So, selling price of the table is Rs. 5x/4
Chair - 10 % profit earned.
So, Selling Price of the chair is -
⇒ SP = y + (y*10)/100
⇒ y + y/10 = 11y/10
Now, according to the question.
⇒ 5x/4 + 11y/10 = 1065
Taking the LCM of denominators and then solving it.
⇒ (25x + 22y)/20 = 1065
⇒ 25x + 22y = 1065*20
⇒ 25x + 22y = 21300 .......................(2)
Now, multiplying equation (1) by 25 and equation (2) by 22, we get
⇒ 550x + 625y = 525000 ............(3)
⇒ 550x + 484y = 468600 ............(4)
Now, subtracting (3) from (4).
550x + 625y = 525000
550x + 484y = 468600
- - -
_____________________
141y = 56400
_____________________
⇒ 141y = 56400
⇒ y = 56400/141
⇒ y = 400
Substituting y = 400 (1)
22x + 25y = 21000
⇒ 22x + (25*400) = 21000
⇒ 22x + 10000 = 21000
⇒ 22x = 21000 - 10000
⇒ 22x = 11000
⇒ x = 11000/22
⇒ x = 500
So, Cost price of table is Rs. 500 and Cost Price of chair is Rs. 400 respectively.
Answer.
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