Question

Manish’s mother is one more than 5 times his present age. 4

years ago the product of their ages is 220. Find their present

age.​

Answer 1

Answer:

There is a error in your question, product of their age is 22 not 220.

let Manish age X

therefore mother's age will be 5x+1

.......... by the given condition.

According to the condition given,

$(x - 4) \times (5x + 1 - 4) = 22$

by the condition.

$= (x - 4)(5x - 3) = 22\\ = 5 {x}^{2} - 3x - 20x + 12 = 22 \\ = 5 {x}^{2} - 23x + 12 = 22\\ = 5 {x}^{2} - 23x - 22 + 12 = 0 \\ = 5 {x}^{2} - 23x - 10 = 0 \\ = 5 {x}^{2} - 25 x + 2x - 10 = 0 \\ = 5x(x - 5) + 2(x - 5) = 0 \\ = (5x + 2)(x - 5) = 0$

therefore, here. .

$5x + 2 = 0 \: \: or \: \: x - 5 = 0 \\ x = - \frac{2}{5} \: \: or \: \: x = 5$

age cannot be negetive.

Therefore Mainsh's age is 5yrs

and his mother's age is 5x+1=5×5+1=25+1= 26yrs

hope it will be helpful

Mark me brainliest

Answer 2

Correct Question:

The present age of Manish's mother is 1 year more than 5 times the present age of Manish. four years before if the product of their ages was 22 then find the present age of Manish and his mother​?

To find:

the present age of Manish and his mother​

SOLUTION:

Let the present Manish age is x

Manish's mother age is 1 year more than 5 times the present age of Manish = 5x + 1

Four years before:

Manish's age = x-4

His mother's age = 5x+1-4

It is given that the product of their ages was 22.

According to the question:

=> (x - 4)(5x+1- 4) = 22

=> (x - 4)(5x - 3) = 22

=> 5x² - 3x - 20x + 12 = 22

=> 5x² - 23x + 12 - 22 = 0

=> 5x² - 23x - 10 = 0

=> 5x² - 25x + 2x - 10 = 0

=> 5x(x - 5) + 2(x - 5) = 0

=> (x - 5)(5x + 2) = 0

=> x = 5 or (-2/5)

The value of x cant be negative so take the value of x is 5

Hence. Manish age = 5 years

Manish's mother age = 5x+1 = 5(5)+1 = 26 years