Math, asked by suspiciousapple5, 7 days ago

Manish sells two watches for Rs 5865 each, gaining 15% on the one and losing 15% on the other. Find (i) the CP of two watches (ii) total gain/loss (iii) Gain/loss percent on the whole transaction.

Answers

Answered by amannida
3

Selling price = S.P

Cost Price = C.P

Given :

Gurpreet sells two watches for Rs 1995 each.

Find the cost price of one watch at gain of 15% :-

C.P = (S.P × 100)/(100 + gain)

= Rs (1995 × 100)/(100 + 15)

= Rs 199500/115

= Rs 1734.78

Find the cost price of other watch at loss of 15% :-

C.P = (S.P × 100)/(100 - loss)

= Rs (1995 × 100)/(100 - 15)

= Rs 199500/85

= Rs 2347.05

We get,

Cost price of two watch = Rs (1734.78 + 2347.05) = Rs 4081.83

Selling price of two watch = Rs (1995 + 1995) = Rs 3990

Here,

Cost Price is greater than the selling price. Therefore, Loss.

Find the loss :-

Loss = C.P - S.P

= Rs (4081.83 - 3990)

= Rs 91.83

Find the loss percent :-

Loss % = (loss × 100)/ C.P %

= (91.83 × 100)/4081.83 %

= 9183/4081.83 %

= 2.249 % approx,

Hence,

His loss percent in the whole transaction = Rs 2.25%

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