Question

. Manisha has a garden in the shape of the rhombus. The perimeter of the rhombus is 40m and its
diagonal is 16m. She wants to divide it into two equal parts and use these parts in rotation.
Find the area of each part of the garden​

Answer 1

Answer:

Hᴇʀᴇ

Area of two equal parts of rhombus = 48m^2

Exᴘʟᴀɴᴀᴛɪᴏɴ

The given garden's shape = rhombus

Fᴏʀᴍᴜʟᴀ ғᴏʀ ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ ʀʜᴏᴍʙᴜs = 4ᴀ

(ᴀ = sɪᴅᴇ ᴏғ ʀʜᴏᴍʙᴜs)

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Perimeter of rhombus. = 40m

Side of rhombus (a). = 40/4 = 10m

Length of one diagonal(m) = 16m

So, second diagonal = n

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a. = √ m^2+n^2

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2×10 = √16^2 + n^2

20^2. = 256 +n^2

400. = 256+n^2

n^2. = 400-256 = 144

n. = 12m

Fᴏʀᴍᴜʟᴀ ᴏғ ᴀʀᴇᴀ ᴏғ ʀʜᴏᴍʙᴜs =  (ᴍ×ɴ)÷2

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m=16m

n =12m

Area = (16×12)÷2

area = 96 sq m

Area of two equal parts = 96÷2

Area of two equal parts of rhombus is

__________

48 sϙ ᴍ

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