Question

Manisha takes 4 rounds along a rectangular park 220m long and 170 m wide. Roshni takes 6 rounds along a square park with side 180m. Who walks more and by how much ?

Answer 1

Answer:

Roshini walks more than Manisha.

Difference = 1560m

Step-by-step explanation:

Area of the rectangular park,

A = 2(l+b) = 2(220+170) = 2(390) = 780m

Roshini walk along,

6(780) = 4680m

Manisha walk along,

4(780) = 3120m

difference = 4680-3120

= 1560m

Answer 2

Before, finding the answer. Let's find out how we can find the answer.

• In this question, we are asked to find who walks more and by how much around parks.
• So, to find that, we have to first find the Perimeter of the Rectangular Park and Square park.
• Then, we must multiply the perimeter by the number of rounds.
• And, at last, to find who walks more, we have to compare both the perimeters and to find by how much we have to subtract the Perimeters of both the Park's.

_________________________________

Given :

• Length and Breadth = 220 m and 170 m
• No of rounds by Manisha = 4
• Side of Park = 180 m
• No of rounds by Roshini = 6

To find :

• who walks more and by how much

Solution :

Perimeter of Rectangular Field = (2 × l) + (2 × b)

                                                   = (2 × 220) + (2 × 170)

                                                   = 440 + 340

                                                   = 780 m

~No of rounds by Manisha = 780 × 4

                                          = 3120 m

Perimeter of Square field = 4 × s

                                          = 4 × 180

                                          = 720 m

~No of rounds by Roshini = 720 × 6

                                         = 4320 m

$\sf \rightarrow Now,$

• Let's compare,

Roshini > Manisha

• By how much?

By how much = 4320 - 3120

                       = 1200

Therefore, the Roshini walks more than Roshini by 1200 m.