Question

Manju had a chocolate. She gave one-
fourth of it to Raji, one-third to Sugatha
and one-sixth to Sheela. She ate the
remaining part. How many pieces of
chocolate did each get? Write here.​

Answer 1

Answer:

Total number of pieces are 12.

Step-by-step explanation:

Given : Manju had a chocolate. She gave one- fourth of it to Raji, one-third to Sugatha  and one-sixth to Sheela. She ate the remaining part.

To find : How many pieces of  chocolate did each get?

Solution :

Let the complete chocolate Manju has be '1'.

She gave one- fourth of it to Raji i.e. $\frac{1}{4}$

She gave one-third to Sugatha i.e. $\frac{1}{3}$

She gave one-sixth to Sheela i.e. $\frac{1}{6}$

First we take a common denominator of all three fraction i.e. 12.

So, Raji would have $\frac{3}{12}$ of the chocolate bar.

Sugatha would have $\frac{4}{12}$ of the chocolate bar.

Sheela would have $\frac{2}{12}$ of the chocolate bar.

Manju ate the remaining,

$R=\frac{(12-3-4-2)}{12}=\frac{3}{12}=\frac{1}{4}$

Therefore, Total number of pieces are 12.

Answer 2

Answer:

Total number of pieces are 12.

Step-by-step explanation:

Given : Manju had a chocolate. She gave one- fourth of it to Raji, one-third to Sugatha and one-sixth to Sheela. She ate the remaining part.

To find : How many pieces of chocolate did each get?

Solution :

Let the complete chocolate Manju has be '1'.

She gave one- fourth of it to Raji i.e. \frac{1}{4}

4

1

She gave one-third to Sugatha i.e. \frac{1}{3}

3

1

She gave one-sixth to Sheela i.e. \frac{1}{6}

6

1

First we take a common denominator of all three fraction i.e. 12.

So, Raji would have \frac{3}{12}

12

3

of the chocolate bar.

Sugatha would have \frac{4}{12}

12

4

of the chocolate bar.

Sheela would have \frac{2}{12}

12

2

of the chocolate bar.

Manju ate the remaining,

R=\frac{(12-3-4-2)}{12}=\frac{3}{12}=\frac{1}{4}R=

12

(12−3−4−2)

=

12

3

=

4

1

Therefore, Total number of pieces are 12.