Question

Manju had a chocolate which has 12 pieces. She gave one fourth of it to Raju, one third to Meena and one sixth to Sheela. She ate remaining part. How many pieces of chocolate did each get?​

Answer 1

Chocolate has 12 equal pieces.

Raju was given (1/4)th chocolate.

Meena was given (1/3)rd chocolate.

Sheela was given (1/6)th chocolate.

Calculation:

According to the question,

Number of pieces of chocolate left with Manju

= 12 - {(1/4) + (1/3) + (1/6)} × 12

⇒ 12 - {(3 + 4 + 2)/12} × 12

⇒ 12 - 9 ⇒ 3 chocolates

∴ The number of pieces of chocolate left with Manju is 3.

Answer 2

$\huge\bf\underline{\underline{\pink{A} \orange{N}\blue{S}\red{W}\green{E} \purple{R}}}$

Total number of pieces are 12.

Step-by-step explanation:

Given : Manju had a chocolate. She gave one-fourth of it to Raji, one-third to Sugatha and one-sixth to Sheela. She ate the remaining part.

To find: How many pieces of chocolate did each get?

Solution :

Let the complete chocolate Manju has be '1'.

She gave one-fourth of it to Raji i.e. 4

She gave one-third to Sugatha i.e. ½

She gave one-sixth to Sheela i.e.

First we take a common denominator of all three fraction i.e.

So, Raji would have of the

chocolate bar. Sugatha would have 2 of the

chocolate bar.

Sheela would have of the 12 chocolate bar.

Manju ate the remaining,

R= (12-3-4-2) = 3 = 1

12 12 4

Therefore, Total number of pieces are 12.

(mark me in brainliest answer please)