Question

Mannu is flying a kite from the top of the house which is 25 m height. The string of the kite is 250 m long when the kite got struck at the top of the tower which is at the distance of 70 m from the house. Find the height of the tower

Answer 1

pls mark me as brainlist

Answer 2

$Height \:of \:the \:house (AB) = 25 \:m$

$Height \:of \:the \:Tower = CD \:m$

$Distance \: from \: base \: of \:the \:tower \\to \: base \:of \: the \: house (BC) = 70 \:m$

$Length \: kite \: string ( AD ) = 250 \:m$

$Let \: DE = x \: m$

$In \: triangle \: AED , \angle {AED} = 90\degree$

$AD^{2} = DE^{2} + EA^{2}$

$\blue {( By \: Phythagorean \:theorem )}$

$\implies 250^{2} = x^{2} + 70^{2}$

$\implies 250^{2} - 70^{2} = x^{2}$

$\implies 62500 - 4900 = x^{2}$

$\implies x^{2} = 57600$

$\implies x =\sqrt{ 240^{2}}$

$\implies x= 240 \:m$

$Now, Height \:of \:the \:tower = CD \\= CE + ED\\= 25 \: m + x \\= 25 \: m + 240 \:m \\= 265 \:m$

Therefore.,

$\red{ Height \:of \:the \:tower}\green {= 265 \:m}$

•••♪