Question

Manoj deposited a sum of Rs. 64000 in a post office for 3years, compounded annually at 7½% per annum . What amount will he get an maturity.​

Answer 1

Answer:

78400

Step-by-step explanation:

64000+64000*3*7.5/100

64000+14400

78400

Answer 2

$\huge \bold{ \green{ ans}{ \orange{wer}}}$

Principal (p) = Rs. 64000

$\huge{ \: rate \: (r) = 7 \times \frac{1}{12} = \frac{15}{2} percent}$

Period (t) = 3 years

$\large{ \sf{ \bold{interest \: for \: the \: first \: year \: = \frac{prt}{100} }}}$

$\large{ \red{rs = \frac{64000 \times 15 \times 12}{100 \times 2} = rs \: 4800}}$

Amount at the end of first year =

$\large{ \sf{rs \: 6400 + rs \: 4800 = 68800}}$

Principal to the second year = Rs. 68800

Interest for the second year =

$\large{ \sf{rs = \frac{68800 \times 15 \times 1}{100 \times 2} = rs = rs \: 5160}}$

Amount at the end of 2nd year =

Rs 68800 + 5160 = Rs 73960

Principal for the third year

$\large{ \sf{ = \frac{7396 \times 15 \times 1}{100 \times 2}}}$

$\large \purple{ \boxed{ \sf{ = 5547}}}$

Amount at the end of 3rd year

$\large{ \sf{rs \: 73960 + rs \: 5547}}$

$\large{ \blue{ \sf{ = 79409 \: \: ans}}}$

hope its help u

$\large{ \star{ \sf{ \fbox{formula \: \: simple \: interest =}}}}$

$\large{ \implies{ \frac{p \times r \times t}{100} }}$

$\large{ \star{ \fbox{compound \: interest}}}$

$\large{ \sf{a = p {(1 + rn)}^{(nt)} }}$

hope its help u