Question

Manoj started 15 minutes late and by travelling at a speed which is 3 by 2 of his usual speed reached his office 5 minutes early what is the usual time of his journey?




iska answer h 60 minutes bt kaise??
jo bhi sahi solution kr k dega use brainlist mark krunga

Answer 1

let us assume he took (T) mins. to travel.
at a speed of "x" . the distance traveled =xT.

Now when he is 15 minutes late and reaches 5 mins earlier than usual,then distance travelled ={3/2x}*(t-20).

now the distance travelled would be the same in the 2 case.

since he reduced the time window by travelling 1.5 times faster.
on equating above 2 equatins we get T=60 mins,which is the required answer

Answer 2

Answer:

Step-by-step explanation:

A=3, B=2 ,T=(15+5)=20

(A/A-B)×T