Question

Manoj takes twice as much as anjay and thrice as much as vijay to finish a piece of work.Together they finish the work in 1 day.What is the time taken by manoj to finish the work.

Answer 1

Answer:

Step-by-step explanation:

Let the work done time by Manoj  be x

And twice as much as anjay so anjay will be $\frac{x}{2}$

And thrice as much as vijay so vijay will be $\frac{x}{3}$

So, they finish work in 1 day.

$x+\frac{x}{2}+\frac{x}{3}=1$

On simplification we get:

$\frac{6x+3x+2x}{6}=1$

$\Rightarrow 11x=6$

$\Rightarrow x=\frac{6}{11}$

So, the work done by manoj will be $\frac{6}{11}$

Answer 2

Answer:Let anjay take 3t days, vijay take 2t days and Manoj take 6t days in order to complete the work. Then we get:

1/3t + 1/2t + 1/6 t =1

by solving we get t= 1

Thus , Manoj would take 6t = 6days (6*1=6) to complete the work

Step-by-step explanation: