Physics, asked by siyapawar1931, 8 months ago

Manoj travels with an average speed of 10 m per second for 20 mins . hiw much does he travel​

Answers

Answered by siddhusujhatha
0

Answer:From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=  

Timetaken

Distance covered

​  

=  

150

300

​  

=2 m/sec

Average velocity=  

Timetaken

Displacement

​  

=  

150

300

​  

=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=  

Timetaken

Distance covered

​  

=  

210

400

​  

=1.90 m/sec

Average velocity=  

Timetaken

Displacement

​  

=  

210

200

​  

=0.95 m/sec

Explanation:if you have another question this answer will be helpful to you

Answered by ayushmahato157
0

Answer:

10×20= 200 m

Explanation:

speed= 10m/sec

time= 20min = 20×60sec= 1200sec

distance=speed×time

=10×1200= 12000 m

Similar questions