manol kumar travelled equal distance with speed of 3km/h ,5km/h & 8km/h and takes a total time of 39.5 minute. Then find the total distance
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7
Solution:
Given,
Speed 1 = 3 km/h
Speed 2 = 5 km/h
Speed 3 = 8 km/h
Time taken = 39.5 minutes
Total speed = 3 km/h + 5 km/h + 8 km/h
Total speed = 16 km/h
Now, convert speed into m/s:
By multipling the km/h from 0.278
16 km/h × 0.278 = 4.44m/s
Now, convert into seconds:
By multipling the minutes from 60
39.5 minutes × 60 = 2,370 s
Firstly recall the formula of distance:
Displacement = Speed × Time taken
Substitute known variables into the equation.
Displacement = 2,370 s × 4.44 m/s
Solve for displacement.
Hence, Displacement = 10522.8 m
Given,
Speed 1 = 3 km/h
Speed 2 = 5 km/h
Speed 3 = 8 km/h
Time taken = 39.5 minutes
Total speed = 3 km/h + 5 km/h + 8 km/h
Total speed = 16 km/h
Now, convert speed into m/s:
By multipling the km/h from 0.278
16 km/h × 0.278 = 4.44m/s
Now, convert into seconds:
By multipling the minutes from 60
39.5 minutes × 60 = 2,370 s
Firstly recall the formula of distance:
Displacement = Speed × Time taken
Substitute known variables into the equation.
Displacement = 2,370 s × 4.44 m/s
Solve for displacement.
Hence, Displacement = 10522.8 m
stanubhattacharyya:
monal kumar travels equal distance with speeds of 3 km/hr.5 km/hr and 8 km/hr and total time taken 39.5 min. find distance
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6
Answer:
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