Question

Mansi buys a bag for Rs 300 from a shop. It is marked 40 percent off. How much will it cost to Mansi? 50 percent of the cost Manasi's mother pays and rest Manasi pays. How much money does Manasi Pay?

Answer 1

C.P. = Rs. 300

Discount = 40 %

S.P. = 300 - 40 % of 300

= 300 - 40 / 100 * 300

= 300 - 40 * 3

= 300 - 120

= Rs. 180

Amount paid by mother = 50 % of 180

= 50 /100 * 180

= 180 / 2

= Rs. 90

Amount paid by Manasi = 180 - 90

= Rs. 90

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Answer 2

Question:

Manasi buys a bag for Rs 300 from a shop. It is marked 40 percent off. How much will it cost to Mansi? 50 percent of the cost Manasi's mother pays and rest Manasi pays. How much money does Manasi Pay?

Answer:

• The actual cost of the bag would be Rs. 500.
• Manasi pays Rs. 150.

Given:

The S.P. of the bag is Rs. 300.

Discount = 40% of M.P.

50% of the money Manasi's mother pays.

The rest of the money Manasi pays.

To find:

• The M.P. cost of the bag.

• The amount of money is paid by Manasi.

Explanation:

Let, the M.P. be, 'n'.

Discount rate = 40%.

∴ Discount = $(n$× $\frac{40}{100} )$

                 = $(n$×$\frac{2}{5})$ [∵ Dividing 40 and 100 by 20.]

                = $\frac{2n}{5}$

Hence,

S.P. = (M.P. - Discount)

       = $(n-\frac{2n}{5})$

       =$(\frac{5n-2n}{5} )$ [∵ The L.C.M. of the denominators is 5.]

       = $\frac{3n}{5}$

∴ According to the problem:

$\frac{3n}{5}$ = 300

⇒ 3n = (300×5)

⇒ n = $(\frac{1500}{3} )$

⇒ n = 500

∴ The actual cost of the bag is Rs. 500.

The S.P.  of the bag is Rs.300.

Manasi's mother pays 50% of the money.

∴ Manasi's mother pays_

Rs. $(300$× $\frac{50}{100} )$

= Rs. ( 3 ×50) [∵ Dividing 300 and 100 by 100.]

= Rs. 150.

∴ Manasi pays = Rs. (300-150)

                        = Rs. 150.

∴ Manasi pays Rs. 150.