Math, asked by sarswatibishnoi93, 8 months ago

Mansi travel 300 kms to her native partly by train by bus , she takes 4hour A she travel 60 kms by train and the remaining by bus . if she travels 100 kms by train and the remaining by bus, she takes 10 minutes , longer find the average speed of the train and the separatly .

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Answers

Answered by Anonymous
1

Answer:

Step-by-step explanation:

Solution :-

Let the speed of train and bus be u km/h and v km/h.        

       

According to the Question,                  

60/u + 240/v = 4 ... (i)                  

100/u + 200/v = 25/6 ... (ii)                  

Putting 1/u = p and 1/v = q in the equations, we get                  

⇒ 60p + 240q = 4 ... (iii)                  

⇒ 100p + 200q = 25/6                  

⇒ 600p + 1200q = 25 ... (iv)                  

Multiplying equation (iii) by 10, we get                  

⇒ 600p + 2400q = 40 .... (v)                  

Subtracting equation (iv) from (v), we get 1200q = 15                  

⇒ q = 15/200 = 1/80 ... (vi)                    

Putting equation (iii), we get                  

⇒ 60p + 3 = 4                  

⇒ 60p = 1                    

⇒ p = 1/60                    

⇒ p = 1/u = 1/60 and q = 1/v = 1/80                    

⇒ u = 60 and v = 80

   

Speed of train = 60 km/h    

Speed of bus = 80 km/h.

HOPE it helps u brother

Answered by BrainlyBAKA
0

\huge\bf\purple{\mid{\fbox{\underline{\underline{Answer}}}}\mid}\\\\

\bf{https://brainly.in/question/37581179}

Let the speed of train and bus be u km/h and v km/h respectively.

According to the question,

\frac{60}{u} + \frac{240}{v} = 4....(i)

\frac{100}{u} + \frac{200}{v} = 4 + \frac{10}{60} = \frac{25}{6} ....(ii)

Let \frac{1}{u} = p\: and \frac{1}{v} = q

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The given equations reduce to:

60p + 240q = 4 ....(iii)

100p + 200q = \frac{25}{6}

600p + 1200q = 25....(iv)

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Multiplying equation (iii) by 10, we obtain:

600p + 2400q = 40....(v)

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Subtracting equation (iv) from equation (v), we obtain:

1200q = 15

q = \frac{15}{1200} = \frac{1}{80}

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Substituting the value of q in equation (iii), we obtain:

60p + 3 = 4

60p = 1

p = \frac{1}{60}

:. p = \frac{1}{u} = \frac{1}{60}, q = \frac{1}{v} = \frac{1}{80}

u = 60 km/h , v = 80 km/h

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Thus, the speed of train and the speed of bus are 60 km/h and 80 km/h respectively.

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