Question

manu is 3 years younger to his sister rimi. if the sum of their ages is 35 years what are their present age?

Answer 1

Answer:

45.7%;54,3%

Step-by-step explanation:

2x+3=35

x=16 ;19

Answer 2

Answer:

Manu age = 16 years

Rimi age = 19 years

Step by step explanation :

Given -:

• Manu is 3 years younger than Rimi
• Sum of there age = 35 years

To Find -:

• Present age of Manu and Rimi

Assume -:

• Let Rimi age be $\rm{x}$
• Then, Manu age = $\rm{x - 3}$

Solution -:

Here both of their assumed age will be equal to 35

$\small \rm{x + (x - 3) = 35}$

$\small\rm {2x - 3 = 35}$

$\small\rm {2x = 35 + 3}$

$\small\rm{2x = 38}$

$\small\rm{x = \frac{38}{2} }$

$\small\rm{x = 19}$

Rimi age = 19 years

Manu age = 19 - 3 = 16 years

Verifying -:

Rimi age + Manu age = 35

19 + 16 = 35

Hence, Verified