Question

Manu is 8 year younger than Beenu and 10 year older then Tiny. the sum of there ages is 136 years. find there ages. ​

Answer 1

Answer:

so let manu's age be x

beenu's age be x+8

Tiny's age be x-10

sum of their ages = 136

so, x+x+8+x-10= 136

therefore x= 46

so their ages are

46, 54 and 36

Answer 2

let manu's age =x

bheenu's age =x+8

Tiny's age= x-10

sum of their ages=136

x+x-10+x+8=136

3x-2=136

3x=136+2

3x=138

x=138/3

x=46

manu=46years

bheenu =46+8=54years

tiny=46-10=36years

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