Question

Manu is 8 years younger than beenu and 10 years older than Tinu. The sum of their ages is 136 years. Find their ages.

Answer 1

Answer:

If Manu is 8 years younger than Beenu and 10 years older than Tinu, then Manu is 46 years old, Beenu is 54 years old and Tinu is 36 years old.

Step-by-step explanation:

Given

Manu is 8 years younger than Beenu and 10 years older than Tinu.

Let x be Manu's age, y be Beenu's age and z be Tinu's age

Given that x= y-8 and x = z+10

That is y-8 = z+10

y= z+ 18

Given the sum of ages = 136

That is 136 = x + y+ z

Substitute x= z+10 and y= z+ 18

That is 136=(z+10)+(z+18)+z

136= 3z+28

3z= 136-28

3z= 108

z= 108/3

z = 36

x= z+10 = 36+10 = 46

y= z+18 = 36+18 = 54

Therefore the age of Manu is 46 years, the age of Beenu is 54 years, and the age of Tinu is 36 years