Manu purchased four oranges at Rs. 10/orange, four oranges at Rs. 25/orange and two oranges at Rs. 30/ orange. Find the average price of an orange
Answers
Answer:
A man buys a certain number of oranges at 20 for Rs. 60 and an equal number at 30 for Rs. 60. He mixes them and sells them at 25 for Rs. 60. What is the gain or loss percent?
5 Answers

Kirti Gupta, B.Sc Mathematics, Indraprastha College for Women, University of Delhi (2018)
Updated October 26, 2019 · Author has 221 answers and 84.1K answer views
He buys some oranges , say x oranges , at 20 for 60 Rs
[math]20 oranges = 60 Rs[/math]
[math]1 orange = 60/20 Rs = 3 Rs[/math]
[math]x oranges = 3x Rs[/math]
Then he buys equal no. Of oranges = x , at 30 for 60 Rs
[math]30 oranges = 60 Rs[/math]
[math]1 orange = 60 /30 Rs = 2 Rs[/math]
[math]x oranges = 2x Rs[/math]
Total Cost Price = 3x + 2x = 5x Rs
He mixes two types of oranges and sells them at 25 for 60 Rs
25oranges=60Rs25oranges=60Rs
1orange=(12/5)Rs1orange=(12/5)Rs
He had x+ x = 2x oranges to sell.
2xoranges=2x×(12/5)R=(24x/5)Ruppees2xoranges=2x×(12/5)R=(24x/5)Ruppees
Selling price = ( 24x/5 ) Rs
C.P - S.P = 5x - (24x/5 )
Loss = x/5
LossLoss
=((x/5)÷5x)∗100=((x/5)÷5x)∗100
=(1/25)∗100=4