Biology, asked by jeelavittal, 11 months ago

manufacturing of TV sets produces 616 3rd year and 716 7th year assuming that the production increases uniformly bhaiya fixit number every year file the production in first seven year the production in 10 year the total production ine 7 years​

Answers

Answered by jayanathul007
0

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Answered by brainly4535
1

Explanation:

Since the production increases uniformly by a fixed number every year. Therefore, the sequence formed by the production in different years is an A.P.

Let a be the first year and d be the common difference of the A.P. formed i.e. 'a' denote the production in the first year and d denotes the number of units by which the production increases every year.

We have,

a

3

=600 and a

7

=700

⟹a+2d=600 ........ (1)

and a+6d=700 ......... (2)

Solving these equation, we get

a=550 and d=25

(i) We have,

Production in the 10

th

year =a

10

=a+9d=550+9×25=775

So, production in 10

th

year is of 775 TV sets.

(ii) We have,

Total production in 7 years

= Sum of 7 terms of the A.P. with first term a(=550) and common difference d(=25).

=

2

7

{2×550+(7−1)×25}

=

2

7

(1100+150)=4375

Thus, the total production in 7 years is of 4375 Tv sets.

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