Question

Many people use a solution of Na3PO4 to clean walls. The recommended concentration is 1.7%(m/v). What mass of Na3PO4 is needed to make 2l of solution

Answer 1

Answer:

Hi !!!

Explanation:

Mass/volume % = mass of solute × 100%

Volume of solution

1.7% = Mass of solute × 100%

(2000ml)

Mass of solute = 34 g

There fore, the required mass is 34 g.

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Answer 2

Mass of Na3PO4 is needed to make 2l of solution = 34g

It is given to us that  $\frac{m}{v}$ % = 1.7 %

The given volume of solution = $2L$ = $2$ × $1000mL$ = $2000mL$

Now,

we know that $\frac{Mass of solute}{Volume of solution }$  ×$100 %$ = $%\frac{M}{V}$$\frac{M}{V}$

So, from the given information we may conclude that -

$\frac{m}{2000mL}$  ×$100$ = $1.7%$

$m$ = $\frac{1.7}{100}$ × $2000 mL$ = $34g$

Therefore, the required mass of $Na_{3} PO_{4}$ is 34g. The compound is also known as TSP.