MAP OF PARK Three friends Aditya, Shreyas and Nikhil have visited the park as they wanted to collect information for their mathematics project. They observed the map of park carefully and made some notes. They observed that length of each small square in given map is 10 m and Ashoka trees were planted in each small square around the park.
Find the dimensions of park.
l=100m, b=100m
l=110m, b=100m
l=110m, b=110m
l=100m, b=110m
Calculate the area in which swings for children have been arranged. *1800 m²
1200m²
600m²
900m²
1800
Find the perimeter of all flowerbeds.
80m
160m
320m
240m
The number of Ashoka trees planted in the park is
35
36
37
34
Find the area marked as “path for walking”
1800m²
1600m²
900m²
800m²
Answers
Answer:
Find the perimeter of all flowerbeds. *
80m
160m
320m
240m
Step-by-step explanation:
Concept:
Area of the park = l × b
Given:
We are given a map of a park.
Length of each small square = 10 m.
Ashoka trees were planted in each small square around the park.
Find:
We need to find:
- The dimensions of the park
- Area in which the swings have been arranged
- Perimeter of all the flower beds.
- The number of Ashoka trees planted in the park
- Area of "path for walking".
Solution:
Number of small square in length = 11
Number of small square in breadth = 11
Length = 11 × 10 m = 110 m
Breadth = 11 ×10 m = 110 m
Dimensions of park:
l = 110 m, b = 110 m
Area for swings = 2 ( l × b )
Area for swings = 2 ( 30 × 20) m²
Area for swings = 1200 m²
Perimeter of 1 flower bed = 4 × side = 4 × 20 = 80 m
Perimeter for 4 flowerbeds = 4 × 80 = 320 m.
Number of small squares in the park = 36.
So, number if Ashoka trees planted = 36
Area of “path for walking” = 2 ( l × b ) = 2 ( 10 × 90 ) m²
Area of “path for walking” = 1800 m²
Therefore, we get that:
- The dimensions of the park are l = 110 m and b = 110 m
- Area in which the swings have been arranged is 1200 m²
- Perimeter of all the flower beds = 320 m
- The number of Ashoka trees planted in the park = 36
- Area of "path for walking" = 1800 m².
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