Question

marathi mein ramzan eid par speech

Answer 1

Answer:

I am Sorry but I don't know Marathi

Sorry bhaaiii..

Answer 2

Answer:

Given that,

Density of acid soln = 1.8 g/ mL.

1000 mL volume will weight 1800g.

Mass of H

2

SO

4

present =1800×

100

90

=1620g

Number of mole of H

2

SO

4

=

molar mass

actual mass

=

98

1620

=16.53 mol

Thus molarity of stock solution is 16.53 M.

To prepare 1000 mL of 0.2 M solution,

M

1

V

1

=M

2

V

2

16.53×x=0.2×1000

x=

16.53

200

x=12.099 ml

x=12.1 ml