Math, asked by amishachavan99, 10 months ago

marbels of diameter 1.4 cm are dropped into a beaker containing some water and are fully submerged the diameter of the beaker is 7 cm find how many marbels have been dropped init the water rises by 56.4​

Answers

Answered by Sravan5380
1

Answer:

201 marbels

Step-by-step explanation:

First take for,

Marbels(Sphere)

Curved Surface Area (CSA) of Sphere=4πr^2

diameter = 1.4

Radius = d/2 = 1.4/2 = 0.7

CSA=4(22/7)(0.7)(0.7)

CSA=6.16

Second for,

Beaker(Cylinder)

Curved Surface Area (CSA) of Cylinder=2πrh

diameter=7

Radius=3.5

CSA=(2)(22/7)(3.5) (56.4)

CSA=1,240.8

Formula

take n = no of marbles

(n)(Area of Marbels) = (Area of Beaker)

(n)(6.16) = (1, 240.8)

n = 201.42 Similarly (~) We can Write as 201

So, the Number of Marbels are 201

This is Correct Process

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