Math, asked by ruej55, 11 months ago

marcus solved for x in the quadratic equation x2 – 10x + 25 = 0.

x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction
x = StartFraction negative (10) plus or minus StartRoot (10) squared + 4 (1)(25) EndRoot Over 2(1) EndFraction
x = StartFraction negative 10 plus or minus StartRoot 200 EndRoot Over 2 EndFraction
What is true about Marcus’s work? Check all that apply.

Marcus should have substituted –10 for b, not 10.
The denominator should be 1, not 2.
Marcus should have subtracted 4(1)(25) in the square root.
This equation, when solved correctly, only has 1 real number solution.
This equation has 2 real number solutions.

Answers

Answered by kamitesh007
2

Answer:

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Answered by hunterjhuggins31794
10

Marcus should have substituted -10for b, not 10

Marcus should have subtracted 4(1)(25) in the square root

This equation, when solved correctly, only has one real number solution

So A, C, D

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