maria bought two fans for ₹3605 . she sold one at a profit of 15% and the other at a loss of 9% . if maria got the same amount for each fan, find the cost price of each fan.
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Answer:
Given, cost price of 2 fans is = Rs 3605 Let cost price of 1 fan be = Rs x Then CP of other fan will be = Rs 3605 – x We know that one is a gain and other is a loss. Selling price of first fan (gain) = x + x×15/100 = x + x×3/20 = (20x+3x)/20 = Rs 23x/20 Selling price of second fan (loss) = (3605 – x) × 91/100 = Rs (3605×91 – 91x)/100 So now, by equating both we get, 23x/20 = (3605×91 – 91x)/100 23x = (3605×91 – 91x)/5 23x × 5 = 3605×91 – 91x 115x + 91x = 3605×91 206x = 3605×91 x = (3605×91)/206 = 1592.50 ∴ Cost price of one fan (x) is = Rs 1592.50 Cost price of second fan (3605 – x) is = 3605 – 1592.50 = Rs 2012.50Rs bought-two-fans-for-rs-3605-she-sold-one-at-a-profit-of-15-and-the-other-at-a-loss-of-9
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