Question

maria bought two fans for Rs 3605. she sold one at a profit of 15% and the other at a loss of 9%. If maria gains the same amount for each fan . find the cost price of each fan.​

Answer 1

Answer:

maybe 2500 I am not clear but it may help you

Answer 2

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

mariam bought two fans for Rs 3605. she sold one at a profit of 15% and the other at a loss of 9%. If maria gains the same amount for each fan . find the cost price of each fan.

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

Step by step explanation:

┏━━━━━━━━━━━━━━━━━━━━━━━┓

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ ✍️

Given :S.P of both fans is same

=>Let C.P of the first fan be ₹x

=>Then C.P of the second fan be ₹(3605-x)

• Profit on 1st fan= 15%
• Loss on 2nd fan=9%

For 1st fan :

$\bold{\boxed{SP = CP( \frac{100 + gain{\&#37}}{100} )}}$

$= x( \frac{115}{100} ) = \frac{23}{20} x$

For 2nd Fan:

$\bold{\boxed{SP = CP( \frac{100 - loss{\&#37}}{100} )}}$

$= (3605 - x)( \frac{91}{100})$

∵ S.P of both the fans is same

$∴ \frac{23x}{20} = (3605 - x)( \frac{91}{100} )$

$\bold{= > 23x \times 100 =[ (3605 - x)20]91}$

$= > 2300x = 91(72100 - 20)x$

$= > 2300x = 91(72100 - 20)x$

$= > 2300x = 6561100 - 1820x$

$= > 4120x = 6561100$

$= > x = 1592.50$

Then C.P of first fan be$\bold{\red{ ₹1592.50}}$

Then C.P of second fan =₹(3605-1592.50)

=$\bold{\red{₹2012.50}}$

┗━━━━━━━━━━━━━━━━━━━━━━━┛