Question

Maria invested rupees 8000 in a business . she would be paid interest at 5% per annum compounded annually .
find
(i) The amount credited against her name at the end of second year .
(ii) The interest for the third year.
​

Answer 1

$\huge \sf\underline\red{Question}$

Maria invested rupees 8000 in a business . she would be paid interest at 5% per annum compounded annually .

Find -:

(i) The amount credited against her name at the end of second year .

(ii) The interest for the third year.

$\huge \sf\underline\red{Solution}$

$\bf \blue{Here \: we \: have,}$

$\fbox \pink{P = Rs.8000}$

$\fbox\pink{R = Rs. 5 \: percent \: p.a}$

$\fbox \pink{n = 2 \: years}$

$\bf \blue{(i) \: Amount \: after \: 2 \: years}$

$\fbox \purple{A2 \: =P(1 + \frac{R }{100} )n }$

$\fbox \purple{ \: =8000(1 + \frac{5 }{100} ) {}^{2} } = \fbox \purple{ = 8000( 1 + \frac{1}{20} ) {}^{2} }$

$\fbox \purple{ = 8000 \times \frac{21}{20} \times \frac{21}{20} } = \fbox \pink{Rs. \: 8820}$

$\bf \blue {A2 = Rs. \: 8820}$

$\sf\green{→Amount \: after \: 2 \: years \: = Rs. 8,820}$

$\bf \blue{(ii)Now \: amount \: after \: 3 \: years}$

$\fbox \purple{A3 \: =P(1 + \frac{R }{100} )n }$

$A3=\fbox \purple{ \: =8000(1 + \frac{5 }{100} ) {}^{3} } = \fbox \purple{ = 8000( 1 + \frac{1}{20} ) {}^{3} }$

$\fbox \purple{ = 8000 ( \frac{21}{20} ) {}^{3} }$

$\fbox \purple{ \frac{8000 \times 21 \times 21 \times 21}{20 \times 20 \times 20} } \: \fbox \pink{Rs. \: 9261}$

$\bf \blue {→Interest \: for \: 3rd \: year \: = A3 -A2}$

$\fbox \orange{Rs.(9261 - 8820)} = \fbox \red{Rs.441.}$

$\sf \green{→So, \: interest \: for \: 3rd \: year \: = Rs.441}$

I am having another version of brainly so my answer is in that way as you see in above attachments⬆️

$\sf\underline\red{Hope \: It \: Helps \: You}$