Mariam bought two fans for Rs 3605. She sold one a
ne at a profit of 15% and the other at a
loss of 9%. If Mariam obtained the same amount 101
wariam obtained the same amount for each fan, and the cost price of each
fan.
Answers
Answer:
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Solution:-
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To find -cost price to table fans
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Let the cost price of table fans be x and y
ATQ
x +y =>3605
=>y=>3605-x (eq1)
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it is given that selling price of both fans are equal
so,
SP of first fan =>x+15℅ =>Rs.115x/100
SP of second fan =>y-9℅ =>Rs.91y/100
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115x/100=91y/100
115x =91y
115x=91(3605-x)
115x+91x=328055
201x =>328055
x=>1592.50Rs.
y =>3605-1592.50
y=>2012.50
hope helps✊
Marks brainliest❤
Answer:
Rs 2012.50
Step-by-step explanation:
Let cost price of 1 fan be = Rs x
Then CP of other fan will be = Rs 3605 – x
We know that one is a gain and other is a loss.
Selling price of first fan (gain) = x + x×15/100
= x + x×3/20
= (20x+3x)/20
= Rs 23x/20
Selling price of second fan (loss) = (3605 – x) × 91/100
= Rs (3605×91 – 91x)/100
So now, by equating both we get,
23x/20 = (3605×91 – 91x)/100
23x = (3605×91 – 91x)/5
23x × 5 = 3605×91 – 91x
115x + 91x = 3605×91
206x = 3605×91
x = (3605×91)/206
= 1592.50
∴ Cost price of one fan (x) is = Rs 1592.50
Cost price of second fan (3605 – x) is = 3605 – 1592.50 = Rs 2012.50