Question

Marilyn solve it!!!!!!!

Answer 1

$\mathbb{\purple{\huge{Hello\:Walkers!!}}}$

$<b><u>Answer</u></b>$

(1) To prove,

AF = 2DC

As EB || DL and ED || BL. Therefore, EBLD is a ||logram.

BL = $ED = \frac{1}{2} AD = \frac{1}{2} BC = CL$

Now in Triangles DCL and FBL, we have,

CL = BL (proved above)

∠DLC = ∠FLB (V.O.A)

∠CDL = ∠FBL (alt. angles)

△DCL = △FBL (AAS)

∴ DC = BF and DL = FL

Now, BE = DC = AB

=> 2AB = 2DC => AF = 2DC


(2) ∵ DL = FL => DF = 2DL


thanks......!

With♥️