Question

MARK 9: The length and breadth of a rectangle are (a² + ab + b2) and (a-b) find perimeter of rectangle.​

Answer 1

Step-by-step explanation:

Given :-

The length and breadth of a rectangle are

(a² + ab + b²) and (a-b).

To find :-

Find perimeter of rectangle?

Solution :-

Given that

Length of a rectangle = (a² + ab + b²) units

Breadth of a rectangle = (a-b) units

We know that

Area of a rectangle = lb sq.units

=> Area of the given rectangle

=> (a²+ab+b²)(a-b)

=> a³-b³ sq.units

We know that

The perimeter of a rectangle =2(l+b) units

Where, l and b are length and breadth

Perimeter of the given rectangle

=> 2[(a²+ab+b²)+(a-b)]

=> 2(a²+ab+b²+a-b) units

Therefore, Perimeter = 2(a²+ab+b²+a-b) units

Answer:-

Perimeter of the given rectangle is 2(a²+ab+b²+a-b) units

Used formulae:-

→ Area of a rectangle = lb sq.units

→ The perimeter of a rectangle =2(l+b) units

• Where, l and b are length and breadth