Math, asked by sudhirwtca41, 11 months ago

mark ant petter borrowed rupees 2250 and rupees2500, respectively at the same rate of simple interest for 3 years, petter paid rupees 45 more as interest than what mark paid, find the rate of interest per annum.​

Answers

Answered by venupillai
5

Answer:

6 per cent per year

Step-by-step explanation:

Mark

P = amount borrowed = Rs.2250

R = rate of interest per cent per year

T = time period in years = 3

SI = Simple Interest = (P*R*T)/100

SI paid by Mark = (2250*R*3)/100

Peter

P = amount borrowed = Rs.2500

R = rate of interest per cent per year

T = time period in years = 3

SI = Simple Interest = (P*R*T)/100

SI paid by Peter = (2500*R*3)/100

Given: Peter paid Rs.45 more as SI than Mark

=> SI of Peter = SI of Mark + 45

=> (2500*R*3)/100 = (2250*R*3)/100 + 45

=> (25*R*3) = (22.5*R*3) + 45

=> 75R = 67.5R + 45

=> 7.5R = 45

=> R = 6

The rate of interest is 6 per cent per year

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