Question

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The sum of areas of two squares is 625cm^2 and the difference of their perimeters is 20cm . Find the length of each square.

Answer 1

HELLO DEAR,


LET THE LENGTH OF SQUARE BE X
AND ANOTHER BE Y

X²+ Y²=625--------------------(1)

4X-4Y=20


X-Y=5 OR ( X=5+Y ) -------------------(2)


(5+Y)²+Y²=625. USING (2)

25+Y²+10Y+ Y²=625


2Y²+10Y-600=0

2y² + 10y - 600

y²+ 5y - 300

(y + 20)(y - 15)

y = -20, y = 15


PUT IN EQUATION(1)


x² + 15² = 625

x² + 225 = 625

x² = 400

x = 20, x = -20


I HOPE ITS HELP YOU DEAR,
THANKS