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The sum of areas of two squares is 625cm^2 and the difference of their perimeters is 20cm . Find the length of each square.
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HELLO DEAR,
LET THE LENGTH OF SQUARE BE X
AND ANOTHER BE Y
X²+ Y²=625--------------------(1)
4X-4Y=20
X-Y=5 OR ( X=5+Y ) -------------------(2)
(5+Y)²+Y²=625. USING (2)
25+Y²+10Y+ Y²=625
2Y²+10Y-600=0
2y² + 10y - 600
y²+ 5y - 300
(y + 20)(y - 15)
y = -20, y = 15
PUT IN EQUATION(1)
x² + 15² = 625
x² + 225 = 625
x² = 400
x = 20, x = -20
I HOPE ITS HELP YOU DEAR,
THANKS
LET THE LENGTH OF SQUARE BE X
AND ANOTHER BE Y
X²+ Y²=625--------------------(1)
4X-4Y=20
X-Y=5 OR ( X=5+Y ) -------------------(2)
(5+Y)²+Y²=625. USING (2)
25+Y²+10Y+ Y²=625
2Y²+10Y-600=0
2y² + 10y - 600
y²+ 5y - 300
(y + 20)(y - 15)
y = -20, y = 15
PUT IN EQUATION(1)
x² + 15² = 625
x² + 225 = 625
x² = 400
x = 20, x = -20
I HOPE ITS HELP YOU DEAR,
THANKS
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