Math, asked by sadhikarachamalla, 10 months ago

Mark for review
Q 61 Determine the number of intercepts with
x-axis of the parabola defined by
equation x2 - 7x + 8.

Answers

Answered by Swarup1998
1

Parabola

To find: The number of intercepts with x- axis of the parabola (x² - 7x + 8).

Solution:

Let, y = x² - 7x + 8

This is the parabola which opens above.

To find intersection by x- axis, we put y = 0.

This gives: x² - 7x + 8 = 0

Now the value of the discriminant is

D = (- 7)² - 4 * 1 * 8

= 49 - 32

= 17 > 0, and thus we can conclude that the equation gives positive values of x.

Therefore the parabola intersects the x- axis at two points.

Number of intercepts = 2.

Note: To find the points of intersection, solve the equation using quadratic formula or use square method.

Read more on Brainly.in

The parabola y^2 = kx makes an intercept of length 2√10 on the line x - 2y = 1. Then k is : (A) 1 (B) -1 (C) 2 (D)-2. Step by step calculation required.

https://brainly.in/question/15809813

Similar questions