Math, asked by vivikajain3, 1 month ago

Mark the correct alternative in each of the following:

1. The sides of a triangle are 16 cm, 30 cm, 34 cm. Its area is

(a) 225 cm² 2. The base of an isosceles right triangle

(b) 240 cm²

(a) 225 cm²

(c) 225 √2 cm²

Its area is

is

30 cm. (b) 225 √3 cm² (c) 225 √2 cm²

3. The sides of a triangle are 7 cm, 9 cm and 14 cm. Its area is

(a) 12√5 cm²

(b) 12√3 cm²

(c) 24 √5 cm²

(d) 450 cm²

(d) 450 cm²

(d) 63 cm²

is

4. The sides of a triangular field are 325 m, 300 m and 125 m. Its area (a) 18750 m²

(b) 37500 m²

5. The sides of a triangle are 50 cm, 78

(b) 30 cm

(c) 97500 m²

and 112 cm. The (c) 40 cm

(d) 48750 m²

smallest altitude is (d) 50 cm

cm

(a) 20 cm 6. The sides of a triangle are 11 m, 60 m and 61 m. The altitude to the smallest side

(a) 11 m

(b) 66 m

(c) 50 m

(d) 60 m

is

7. The sides of a triangle are 11 cm, 15 cm and 16 cm. The altitude to the largest side in

(a) 30 √7 cm

15/7 2 (b) cm

(c) 15/7 4 cm

(d) 30 cm

8. The base and hypotenuse of a right triangle are respectively 5 cm and 13 cm long. Its a

is

(a) 25 cm²

(b) 28 cm²

(c) 30 cm²

(d) 40 cm²

9. The length of each side of an equilateral triangle of area 4√3 cm², is

(a) 4 cm

4 √3 (b) cm

(c) cm 4

10. If an isosceles right triangle has area 8 cm², then the length of its hypotenuse is

(a) √32 cm

(b) √48 cm (c) √24 cm

11. The perimeter of an equilateral triangle is 60 m. The area is

(a) 10/3 m²

(b) 15√3 m²

(c) 20/3 m²

(d) 4cm

12. The area of an isoscles triangle having base 2 cm and the length of one of the equal s 4 cm, is

(a) √15 cm²

√15 2 (b) cm

(c) 2√15 cm²

(d) 4/15 cm²

(d) 3 cm

(d) 100-/3 m²

13. The length of each side of an equilateral triangle having an area of 9/3cm² is

(a) 8 cm

(b) 36 cm

(c) 4 cm

(d) 6cm​

Answers

Answered by Barani22
1

Answer:

options b

options c

options a

options a

options d

options c

bro please mark as best answer true

options d

Given sides of triangles are a=16cm,b=30cm,c=34cm respectively

Semiperimeter s=

2

16+30+34

cm

=

2

80

=40cm

By heron's, area of the triangle is

s(s−a)(s−b)(s−c)

cm

2

=

40(40−16)(40−30)(40−34)

cm

2

=

40×24×10×6

cm

2

=

4×10×4×6×10×6

cm

2

=4×6×10cm

2

=240cm

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