Question

Mark the correct alternative in each of the following: A die is thrown once. The probability of getting a prime number is
(a)$\frac{2}{3}$
(b)$\frac{1}{3}$
(c)$\frac{1}{2}$
(d)$\frac{1}{6}$

Answer 1

SOLUTION :  

The correct option is (c) : 1/2

Given : A die is thrown once .

A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.

If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6

Number of possible outcomes are = 6

Let E = Event of getting a prime number

Prime number in a die = 2, 3, 5  

Number of outcome favourable to E = 3

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 3/6  = ½  

Hence, the probability of getting a  prime number , P(E) = 1/2

HOPE THIS ANSWER WILL HELP  YOU…

Answer 2

refer to the attachment